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How do I convert r^2 sin(2 theta) = 5 to Cartesian Form
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you might want to review your trig identites
sin 2t = 2sin(t)cos(t) might be useful in getting some xy parts written up
2xy = 5 comes to mind
x = r cos y = r sin r^2 sin(2 theta) = 5 r^2 2sin cos = 5 2 rsin rcos = 5 etc ...
Thank you very much, that was really helpful!
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your welcome :)
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