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Solve by elimination 9x^2 + y^2 = 85 2x^2 - 3y^2 = 6
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Mutliply 1st eq with 3
What do you get?
So 1st equ. is 27x^3+ 3y^2 = 225
2x^2 + 27x^3 = 231
27x^3 o_O?
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opps 29x^2
the same power
Now divide 231 with 29
7.96 take the square root 2.822
Wait you mutilpied wrong...
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9x^2 + y^2 = 85 2x^2 - 3y^2 = 6 First eq mutiply by 3 will be 27x^2+3y^2=255
So, 27x^2+3y^2=255 2x^2 - 3y^2 = 6 =========== 29x^2=261 divide 261 with 29 x^2=9
i see ...9 take the square root x=3
Ya!
substitute the x value to find y right?
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Yes! in the ORIGINAL second eq i.e 2x^2 - 3y^2 = 6
y = square root of 10
2(9)-3y^2=6 18-3y^2=6 subract 18 both sides 18-3y^2=6 -18 -18 ========= -3y^2=-12 y^2=-12/-3 y^2=4
y=2
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