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2sqrt(11) times 8sqrt (22) @phi
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multiply them you can use the rule that \[ \sqrt{a}\cdot \sqrt{b}= \sqrt{a\cdot b} \]
sqrt(242)
don't forget the stuff out front also, it is best not to actually multiply out 11*22 because you should factor the 22 into 2*11, so you have 11*11*2 because you want to find pairs to take out of the square root.
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