Question

Find the solution set
(2x-1)^2-3(2x-1)=-2

Answer 1

\[(2x-1)^2-3(2x-1)^2+2=0\] solve
\[w^2-3w+2=0\] then replace \(w\) by \(2x-1\) and solve for \(x\)

Answer 2

pretty easy in this case because
\[w^2-3w+2=0\] factors as
\[(w-2)(w-1)=0\] making
\[w=1\] or \[w=2\] so your only job now is to solve
\[2x-1=1\] and \[2x-1=2\] for \(x\)

Answer 3

okay :)

Answer 4

you good from there right?

Answer 5

yes, thank you :) ill try to solve it on my own

Answer 6

x=1 and x=3/2