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solve each equation. z^2 - 6z - 27 = 0 ?
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This is a Quadratic equation...right?
@uri what have you been eating :)
Nothing...it was ramadan remember...why? @dlearner
\[z^2-9z-3z-27=0\]\[(z+3)(z-9)=0\]
is that correct @deena123
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u can check it if u want @broderick365
this was the wrong equation the equation is z^2 - 6z - 27 =0 ? @deena123
sory a typo from my side it should be -9z+3z instead of -9z-3z
z^2 - 6z - 27 The number when adding or subracting should be -6 so,-9+3=-6 and when multiplying should be 27 so,9 x 3=27 So, z^2-9z+3z-27 z(z-9)+3(z-9)
Answer will be :(z-9)(z+3)
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