Question

how do you isolate X or Y?

(3/x) + (2/y) = 16
(2/x) - (1/y) = -1

I can't seem to succeed in doing it :(

Answer 1

\[put \frac{ 1 }{ x }=u,\frac{ 1 }{ y }=v and then solve\]

Answer 2

what do you mean?
I only get this:
\[3y + 2x = 16xy\]

Answer 3

3u+2v=16
2u-v=-1
solve for u and v

Answer 4

finally u=1/x orx=1/u,y=1/v

Answer 5

@surjithayer apply cal3 ?? change variable ?

Answer 6

3u+2v=16 ...(1)
2u-v=-1 ...(2)
(1)+2(2)
3u+2v+4u-2v=-2
7u=-2
u=-2/7
from(2)
2*-2/7-v=-1
-4/7+1=v
v=3/7
u=-2/7,1/x=-2/7,x=-7/2
v=3/7,1/y=3/7,y=7/3