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Identify the 8th term of the geometric sequence -2, -12, -72 ...
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-2 times 6 is -12 times 6 is -72 times 6 is.... just keep multiplying by 6 until you get the eight term. or save time by just multiplying -2 by 6^7
notice the common ratio is 6, thus \(\bf \Large a_n = a_1 \times r^{n-1}\) n = nth term 1 = 1st term r = common ratio
\[\large a_n = a_1r^{n-1}\]using this formula,first figure out the r (ratio). Divide the preceding number by the first number, \(\large \frac{-12}{-2}= 6 \ ...\frac{-72}{-12}=6\) so we know our r= 6. Our n is the # of terms we are trying to find, that is the 8th term. n=8 Plugging this into our formula, we will have \(\large a_8 = (-2)(6)^{8-1}\)
\[\large a_8 = (-2)(6^{7}) = \ ?\]
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