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OpenStudy (anonymous):
2x+1= square root 3x^2+5x+3 solve the equation for x. if necessary round your answer to two decimal places.
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OpenStudy (anonymous):
\[2x+1=\sqrt{3x ^{2}+5x+3}\]
OpenStudy (anonymous):
i got x=2,-1
OpenStudy (anonymous):
try plugging both back into the original equation to see if they match on both sides
OpenStudy (anonymous):
just 2 does.
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