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9n^2=4
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@user2486 @agent0smith
since your solving for n what do you think would be the first step?
get n on one side so divide 9
n^2=4/9
ok now to get rid of a square you take the square root of both sides
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\[\sqrt{n^2}=\sqrt{4/9}\]
\[n=\sqrt{4/9}\]
Is that it?
you can simplify the sprt(4/9) What is the square root of 4 and what is the square root of 9?
2 and 3
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\[n=\sqrt{2/3}\]
you took the square root so it goes away other than that you are right
n=2/3?
yes good job
k
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