Question

over the set of real numbers, what is the domain of the opposite function g(f(x))?

Answer 1

\[f(x)=-x-3,g(y)=\sqrt{y} g(f(x))=\sqrt{-3-x}\]

Answer 2

help please

Answer 3

would the answer be \[x \le3\]

Answer 4

you have to solve
\[-3-x\geq 0\] which you do in one step by adding \(3\) to both sides

Answer 5

but you do not get \(x\leq 3\) you get \(x\leq -3\)

Answer 6

my bad i forgot the sign