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what is the value of cos(npi/2)
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I don't know. Check these. http://answers.yahoo.com/question/index?qid=20070314101632AABfxtA http://math.stackexchange.com/questions/53202/how-do-you-solve-this-series-question-cos-n-pi-ln6n
@harsid Those links don't really relate to the asked problem. Anyway, assuming that \(\bf n\) is an integer, we have the following:\[\bf \cos \left( \frac{ n \pi}{ 2 } \right)=0 \ | \ n=\frac{ \pi }{ 2 }+2 \pi k \ \ or \ \ n=\frac{ 3 \pi }{ 2 }+2 \pi k, \ k \in \mathbb{Z}\]
You could also say that the values lies within 1 and -1 for real numbers 'n'...
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