Question

suppose that the population of deer in state is 1,500 and is growing 2% each year.predicit the population after 4 years.
a. about 12,000 deer.
b.about 1,624 deer.
c. about 3,110 deer.
d. about 24,000 deer.
need help.and explain plz.

Answer 1

\[P_n=1500·(1+0.02)^n=1500·1.02^n\] Solve for n=4

Answer 2

The formula is obtained like this:
Current Population=P0=1500
After 1 year: P1=P0+0.02·P0=P0·(1+0.02)
After 2 years:P2=P1+0.02·P1=P1·(1+0.02)=P0·(1+0.02)·(1+0.02)=P0·(1+0.02)^2
After 3 Years:P3=P2·(1+0.02)=P0·(1+0.02)^2(1+0.02)=P0·(1+0.02)^3
Same rationale to get P4=P0·(1+0.02)^4=1500·1.02^4

Answer 3

so the answer will be a.12,000 deer

Answer 4

wrong calculation, try again

Answer 5

Give me 1.02^4

Answer 6

you there?

Answer 7

yes

Answer 8

give me 1.02^4

Answer 9

1.08

Answer 10

Now 1.08 times 1500

Answer 11

sure

Answer 12

1.02^4 is not 1.08

Answer 13

got it the answer is B. 1,624 deer

Answer 14

It is a bit more than 1.08

Answer 15

@redapple then the answer is:????

Answer 16

do you think is 3,110 deer

Answer 17

It is B

Answer 18

thanx 4 the help.

Answer 19

welcome

Answer 20

(9*10^5)(6*10^-7)
a. 5.4*10^-34
b.1.5*10^-1
c.5.4*10^-1
d.1.5*10^34
need help plz.

Answer 21

Some help for you:\[(x·10^n)·(y·10^m)=(x·y)·10^{(n+m)}\]