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What is the exact value of the square root of the quantity 27 over 64.? 3 the square root of 3 all over 4. 9 the square root of 3 all over 4. 9 the square root of 3 all over 8. 3 the square root of 3 all over 8.
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\[\sqrt{\frac{27}{64}}=\frac{\sqrt{27}}{\sqrt{64}}\] is a start the denominator is easy, right?
i.e. what is the square root of 64?
8
ok good so you can ignore answers 1 and 2 denominator is 8
as for \(\sqrt{27}\) , note that \(27=9\times 3\) and so \(\sqrt{27}=\sqrt{9\times 3}=\sqrt{9}\sqrt{3}\) what is \(\sqrt{9}\) ?
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3 so D
3 the square root of 3 all over 8.
yes, D
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