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A diameter of a circle x^2+y^2-4x-2y+3=0 passes through (1,3). Find the equation of this diameter (I already found the midpoint, what do I do next?)
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you have the mid point which is the center and another point is given, so where is the problem ?
Mm, I'm not so sure how to sub it in the formulas~or which one in the list to use :P
I already got it xD
okay you have m is the slope and equals \[\Delta y /\Delta x\] and you have y=mx+b you just substitute for any point you like between the two you have and you will get it
Yep yep, got it mate, thanks xD
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you are welcome :)
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