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Find the limit of the function algebraically. limit as x -->9 of quantity x^2-81/x-9 .
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\(x^2-81\) is a difference of squares... consider \(x^2-81=x^2-9x+9x-81=x(x-9)+9(x-9)=(x-9)(x+9)\)
THANKS @oldrin.bataku
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