Question

Find the quotient of quantity of 6 times x to the 3rd power minus 18 times x to the 2nd power minus 12 times x all over negative 6 times x.

−x2 − 3x − 2

x2 − 18x − 12

−x2 + 18x − 12

−x2 + 3x + 2

Answer 1

\[\frac{ 6x^3-18x^2-12x }{ -6x }\]

Answer 2

devide each term individually so you get
d) -x^2 + 3x +2

Answer 3

thank you

Answer 4

you are welcome