Question

Is this proof acceptable for showing how Triangles DEF and DEG are similar?

Answer 1

Angle DEF = 60 degrees - Given
Angle EFD = 60 degrees - Given
Angle DEF = Angle EFD - Transitive Property of Equality
Angle EDF = Angle EDF - Reflexive Property of Equality
Triangle DEF ~ Triangle DEG - AA Similarity Postulate

Answer 2

I would say that Angle DEF = Angle EFD is true by substitution

Answer 3

and I would change Angle EDF = Angle EDF to Angle EDF = Angle EDG

the reason for this change is because one of the triangles does not have F in it

Answer 4

the reason I would use for Angle EDF = Angle EDG is "shared angles" or "common angles" since they overlap

everything else looks great