Question

1-sin(x/2)=0 on [0, 2pi]

Answer 1

\[1-\sin(\frac{x}{2})=0 \rightarrow -\sin(\frac{x}{2})=0-1 \rightarrow \sin(\frac{x}{2})=1\]
\[\sin(\frac{x}{2})=\sin(\frac{\pi}{2}) \rightarrow \frac{x}{2}=\frac{\pi}{2} \rightarrow x=\pi\]