Question

1-tanx/1-cotx

Answer 1

(1-tanx)/(1-cotx)?

Answer 2

tan x= sinx/cosx. cot x= cosx/ sinx is something you should know.

Answer 3

(1-sinx/cosx)/(1-cosx/sinx)= ((cosx-sinx)/cosx)/( (sinx-cosx)/sinx)

Answer 4

I end up getting tanx but im pretty sure it should be -tanx

Answer 5

\[\begin{align*}\frac{1-\tan x}{1-\cot x}&=\frac{1-\frac{\sin x}{\cos x}}{1-\frac{\cos x}{\sin x}}\\\\
&=\frac{\frac{\cos x-\sin x}{\cos x}}{\frac{\sin x-\cos x}{\sin x}}\\\\
&=-\frac{\frac{1}{\cos x}}{\frac{1}{\sin x}}\\\\
&=-\frac{\sin x}{\cos x}\\\\\\\\
&=\cdots
\end{align*}\]