Question

the perimeter of a rectangle is 10 ft. the length is 1 ft longer than the width .find the dimensions.writer a system of linear equations and solve the resulting systerm. let x be the length and y be the width.

write the first equation.2x+2y=

write the second equation. x=y+

what is the length?__ft
what is the width?__ft

Answer 1

im lost

Answer 2

Let x be the width of the rectangle. Then width=?

Answer 3

sorry..length=?

Answer 4

im so lost

Answer 5

no you are not :) tell me what the length is ........

Answer 6

right...a hint: the length is 1 ft longer than the width

Answer 7

so if the width is x..then length =?

Answer 8

i do not know

Answer 9

i don't buy it..just read the above posts and gimme an answer.don't matter if its wrong

Answer 10

1 and 5x

Answer 11

what is 5x?

Answer 12

length

Answer 13

if x is width...5x is length. is that what you mean?

Answer 14

yes

Answer 15

how can that be if the length is 1 ft longer than the width

Answer 16

ok im dumb

Answer 17

look..what is 2 in terms of 1??

Answer 18

A) 2x+2y= 10
B) x-y= 1
changing equation B
x = y + 1
Substituting that into equation A)
A) 2 *(y+1) + 2y = 10
2y + 2 + 2y =10
4y = 8
y = 2 feet
x = Y +1 so x = 3 feet

Answer 19

write the first equation.2x+2y=10 is right

Answer 20

write the second equation. x=y+ is 1 right

Answer 21

what is the length?__ft is 2feet
what is the width?__ft is 3feet

Answer 22

write the first equation.2x+2y=10 is right
write the second equation. x=y+ is 1 right
what is the length?__ft is 2feet
what is the width?__ft is 3feet