Question

am i correct? division
(3x^(2)-12x)/(2x-7)÷(x-4)/(2x-7)

answer = 3x/2-3/4-21/4(2x-7)
am i right?

Answer 1

\[\frac{3x^2 - 12x}{2x - 7} \div \frac{x - 4}{2x - 7}\]

You have to reciprocate the second fraction then multiply:

\[\frac{3x^2 - 12x}{2x - 7} \times \frac{2x - 7}{x - 4}\]

Also, you have to cancel factors of one:

\[\frac{3x\cancel{(x - 4)}}{\cancel{2x - 7}} \times \frac{\cancel{2x - 7}}{\cancel{x - 4}}\]

Answer 2

so the answer is 3x? im not good at math sorry lol

Answer 3

Yes, but you should learn how to do these.

Answer 4

yes i know im trying to learn thanks

Answer 5

khan academy can teach you