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Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. A survey of 300 union members in the New York State reveals that 112 favor the republican candidate for governor. Construct the 98% confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.
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\[\frac xn\pm z_{\%}\sqrt{\frac{x(n-x)}{n^3}}\]
since texts seem to use the pq format these days: p = x/n; q = (n-x)/n which gives us the other setup\[p\pm z_{\%}\sqrt{\frac{pq}{n}}\]
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