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find the solutions to the equation below. Check all that apply. x^2+14x+40=0 A.X=-10 B.x=6 C.x=-8 D.x=-4 E.x=4 F. X=3
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\[(x+4) (x+10) = 0\]What do you think?
c
Not quite... From the factored out equation, the addition sign means the solutions will be negative...
C or D are the only negative ones
What about A?
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yup and a
OKay, so what's the answer? Don't guess!
let me factor it
What two numbers when added together make 14 and when multiplied together make 40?
Dude, it is already factored..... \[x^2+14x+40=0 \]\[(x+4)(x+10)=0 \]
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4 nd 10
positive or negative? what letters?
D nd A
YES! CORRECT
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