Question

find the solutions to the equation below. Check all that apply.
4x^2-4x-3=0
A.X=-1/2
B.x=-2
C.x=1/2
D.x=2
E.x=3/2
F. X=3

Answer 1

Can you do this one on your own? Or do you want me to start it?

Answer 2

answers have to + huh

Answer 3

let me try and just check my answer

Answer 4

No necessarily.... When you answer is like the one below, you have a positive AND a negative\[ax^2 - x - b^2\]

Answer 5

got it A nd E

Answer 6

YUPPERS

Answer 7

\[4x^2-4x-3=0 \]\[(2 x-3) (2 x+1) = 0 \]\[x = -\frac{ 1 }{ 2 }, \frac{ 3 }{ 2 }\]