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If cosx=-3/5 and pi
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cos x = -3 / 5 pi < x < 3pi / 2 -> x is in the third quadrant. cos^2 (x / 2) = (1 + cos 2(x / 2)) / 2 = (1 + cos x) / 2 cos (x / 2) = -sqrt ((1 + cos x) / 2) = - sqrt ((1 - 3 / 5) / 2) = - sqrt (1 / 5) = -1 / sqrt 5 = - sqrt 5 / 5 It is negative because cosine x is negative in the third quadrant.
wow thanks!
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