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2bx+cy+cx+2by
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(x+y)(2b+c)
how did you regroup??
I see that there is a common between 2bx+2by and cy+cx And you can see also that there is a common monomial between them Right .. Then Factor it , it mean your need to extract their common . (2bx+2by) (cy+cx) use common monomial 2b(x+y) + c(y+x) if u see that we have 2 X+y so we need to copy it by ones then copy the expression outside the parenthesis so your answer is (2b+c) (x+y)
tell me if you get it ? :)
@Algebra2013 Did u get it
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got it thanks again
Your welcome
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