Question

Put the equation in the form ax^2+bx+c=0. Enter exponents using the caret (^).
9-5x^2=(x-2)^2-4

Answer 1

We already answered this... Remember? \[-6 x^2+4 x+9 = 0\]

Answer 2

i dont know how to do it can you help mee please

Answer 3

We wrote it on the History one!

Answer 4

http://openstudy.com/study#/updates/52092d95e4b01dd6868af49e

Answer 5

9−5x2=(x−2)2−4
9−5x2=x2−4x

−6x2+4x+9=0

Answer 6

Yes! You move everything to the left side...