Question

Put the equation in the form ax^2+bc+c=0
(2x+1)^2-3x=5

Answer 1

let me try kay

Answer 2

2x^2-3x+5=0

Answer 3

YOU BETTER TRY IT :P
\[(2x+1)^2-3x=5 \]\[4 x^2+x+1 = 5\] You finish...

Answer 4

damnn i suck at this xD

Answer 5

did you figure it out?