PRECALCULUS QUESTION
*Part III: Solve the problem for E, the energy released by the earthquake.*

Question

PRECALCULUS QUESTION 
*Part III: Solve the problem for E, the energy released by the earthquake.*

anonymous · Answer

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anonymous · Answer

Can You Please Help me With the question I Posted?

anonymous · Answer

@Yika3040 okay, just go to it! I'll be right there...

anonymous · Answer

Part I: Rewrite the equation for the magnitude of an earthquake, using the magnitude of 7.5 given in the problem:

$$R = 0.65\log(0.39 \times E) + 1.45$$$$7.5 = .65\log(.39 \times E) + 1.45$$

anonymous · Answer

Part II: Simplify the problem so that it is written in the form b = log(a)

$$b = log(a)$$$$7.5=.65\log(.39×E)+1.45 $$$$9.307692= \log(.39E)$$

anonymous · Answer

I asked my friend, but he got this: $$E = 5.20748 \times 10^9$$

anonymous · Answer

can you help me with the question i just posted?

anonymous · Answer

@Yika3040  Go to your question, and I'll be right there :)