Question

PRECALCULUS QUESTION
*Part III: Solve the problem for E, the energy released by the earthquake.*

Answer 1

Can You Please Help me With the question I Posted?

Answer 2

@Yika3040 okay, just go to it! I'll be right there...

Answer 3

Part I: Rewrite the equation for the magnitude of an earthquake, using the magnitude of 7.5 given in the problem:

\[R = 0.65\log(0.39 \times E) + 1.45\]\[7.5 = .65\log(.39 \times E) + 1.45\]

Answer 4

Part II: Simplify the problem so that it is written in the form b = log(a)

\[b = log(a)\]\[7.5=.65\log(.39×E)+1.45 \]\[9.307692= \log(.39E)\]

Answer 5

I asked my friend, but he got this: \[E = 5.20748 \times 10^9\]

Answer 6

can you help me with the question i just posted?

Answer 7

@Yika3040 Go to your question, and I'll be right there :)