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perform the operation on complex numbers @Isaiah.Feynman @ilfy214 @seesawn
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\[(2+i)/(3+2i)\]
Operation?
like simplify i think
Okay well try to get rid of your denominator multiplying your num and denim by (3+2i) \[\frac{ (2+i)}{(3+2i)}\] \[\frac{ (2+i)}{(3+2i)} \times \frac{ (3+2i)}{(3+2i)} \]
what/
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how
multiply? You know how
i mean like am i cross multiplying
Hold on. I meant THIS: \[\frac{ (2+i)}{(3+2i)} \times \frac{ (3-2i)}{(3-2i)}\]
And you do not cancel anything out here
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i got 8/13-1/13
@ilfy214
almost... not 1! \[\frac{ 8}{13}-\frac{ i}{13}\]
ooo ok
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