A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year he earned $112 in interest. How much money was invested in each account?

Which of the following equations could be used to solve the problem?

0.02x + 0.04(800) = 112
0.02x + 0.04(x + 800) = 112
0.04x + 0.02(x + 800) = 112

Question

A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year he earned $112 in interest. How much money was invested in each account?

Which of the following equations could be used to solve the problem?


0.02x + 0.04(800) = 112
0.02x + 0.04(x + 800) = 112
0.04x + 0.02(x + 800) = 112

anonymous · Answer

I=P*R*T

anonymous · Answer

i think probably thts what the lesson is based on

anonymous · Answer

0.04x + 0.02(x + 800) = 112
I'm pretty sure.