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Solve the equation logbase27 x = 1 – logbase27 (x – 0.4).
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\[\log_{27}x=1-\log_{27}(x-.4) \]
\[\log_{27}x+\log_{27} (x-.4)=1 \]
\[\log_{27}x(x-.4) =1\]
x^2-0.4x=27?
\[27^{1}=x(x-.4)\]
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Solve that quadratic equation.
Funny thing is I did all that xD
I got stuck at the quadratic
x^2-.4x=27 10x^2-4x-270=0
\[2(x-5)(5x-27)=0\]
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And, of course, if you had trouble factoring, you could always use the quadratic formula.
Nahh, I gots it from there thanks (=
yw
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