Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of (– 2, – 16), and x intercepts at x = -6 and x = 2. (Do not include the negative sign in your answer.) y = x2 + 4x − ___
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OpenStudy (anonymous):
write you x-intercepts in factored form and expand it.
OpenStudy (anonymous):
Can you explain?
OpenStudy (anonymous):
x intercepts at x = -6 and x = 2, right?
so factored form is y= (x-r)(x-s), where r= -6 and s= 2. plug it in then expand it..
OpenStudy (anonymous):
y=(x--6)(x-2)
OpenStudy (anonymous):
so it will be like this: y=(x+6)(x-2).. expand this
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OpenStudy (anonymous):
y=x^2-2x+6x-12
OpenStudy (anonymous):
simplify
OpenStudy (anonymous):
x^2+4x-12
OpenStudy (anonymous):
there you go, you already have the answer.. just look at it and find the missing term:)
OpenStudy (anonymous):
Can you explain to me what the answer is because im still not so sure @Data_LG2
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OpenStudy (anonymous):
y = x2 + 4x − ___.. compare this to your answer above.. the missing term will be ...
OpenStudy (anonymous):
-12
OpenStudy (anonymous):
?
OpenStudy (anonymous):
@Data_LG2
OpenStudy (anonymous):
kind of.. read your question again and it says: (Do not include the negative sign in your answer.) so the answer is?
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