Question

Can anyone help me with a couple problems....... Please I will become a fan and give you a medal. I'm very confused and I dont know really how to figure it out. You dont have to give me the answer just help me set it up and then check my answer

Answer 1

@yummydum

Answer 2

where's the question..?

Answer 3

Divide: 7 times a plus 28 all over the quantity a minus 4, end quantity. ÷ a squared plus a minus 12 all over the quantity 14 times a, end quantity.

Answer 4

\[{7a+28\over{a-4}}\div {a^2+a-12\over14a}\]
Yes?

Answer 5

yup

Answer 6

okay so I'm sure you know of "Keep it, Change it, Flip it" ...so let us do that! \[{7a+28\over{a-4}}\div {a^2+a-12\over14a}~~~\implies~~~{7a+28\over{a-4}}\times {14a\over a^2+a-12}\]
now just multiply across:\[(7a+28)(14a)\over(a-4)(a^2+a-12)\]
factor:\[{7(a+4)(14a)\over(a-4)(a-3)(a+4)}~~~\implies~~~{7(14a)\over(a-4)(a-3)}\]
and so you're left with:\[98a\over a^2-7a+12\]

Answer 7

oh okay

Answer 8

Oh now I understand!!!!!!! THANK YOU(:

Answer 9

No problem!

Answer 10

AND U WERE RIGHT!

Answer 11

Lol, glad I could help! :)