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Mathematics 9 Online
OpenStudy (anonymous):

solve for x . 12x^2 = 3x

OpenStudy (akashdeepdeb):

12x2 - 3x = 0 take x common --> x(12x - 3) = 0 Thus x can be 0 [IF YOU TAKE 12x - 3 to the LHS] or it can be 12x - 3 = 0 [IF YOU take x to the LHS] --> x = 1/4 Thus can be 0 or 1/4! :) I hope this helped! :)

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