Question

Solve ΔABC with A = 61°, b = 33, and c = 39.

Answer 1

use law of cosines to find side "a"
\[a^{2} = 33^{2}+39^{2}-2(33)(39)\cos 61\]

Answer 2

then find angle B using Law of sines
\[\frac{\sin B}{33}=\frac{\sin 61}{a}\]

then
C = 180-61-B

Answer 3

can you give me anymore help

Answer 4

well ive laid out the steps...the rest is just computing

Answer 5

okay