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If I have an right triangle with one angle measuring 53 degrees and a side measuring in 6 inches how do I find the other two sides?
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I have already found angle 37 degrees
Which would I use?
\(\bf sin(\theta) = \cfrac{b}{c} \implies b = sin(\theta)\times c\) and so on
just solve the trig identity, for the "missing side"
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So x over 6in
Wait which one is a over b
a/b ahemm, adjacent/opposite
ohh, not in the picture ... yes I see hmm, well use b/a :) then
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