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Mathematics 18 Online
OpenStudy (anonymous):

(3+2i)+(7-5i)

OpenStudy (raffle_snaffle):

What is the question

OpenStudy (anonymous):

write the sum (3+2i)+(7-5i) in standard form

OpenStudy (anonymous):

\[10-3i\]

OpenStudy (anonymous):

can you tell me how?

OpenStudy (isaiah.feynman):

@mayafrancis Gooooooood job!

OpenStudy (raffle_snaffle):

You add the components

OpenStudy (anonymous):

ohhhh ok. thankssss.

OpenStudy (anonymous):

Multiply i and 2 Multiply i and 1 The i just gets copied along. The answer is i i 2*i evaluates to 2i 3+2*i evaluates to 3+2i Multiply i and 5 Multiply i and 1 The i just gets copied along. The answer is i i 5*i evaluates to 5i 7-5*i evaluates to 7-5i To add the polynomials 3+2i and 7-5i we try to add or combine terms in one polynomialwith any like terms in the other polynomial. 3 + 7 = 10 2i + -5i = -3i The answer is 10-3i (3+2*i)+(7-5*i) evaluates to 10-3i

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