Question

factor completely:
see below:

Answer 1

\[125m ^{3}-8x ^{3}\] = \[(5m-2x)(25m ^{2}+10mx+4x ^{2}\] can someone please explain how to get the +10mx???????????????

Answer 2

I can't figure out how to get the middle number??

Answer 3

\[a^3 – b^3 = (a – b)(a^2 + ab + b^2)\\you \space have\space a=5m, b=2m\\so\\125m^3-8x^3 = ((5m)^3)-(2m)^3)=(5m-2x)(25m^2+10mx+4x^2)\]

Answer 4

how did you figure middle number? 10mx

Answer 5

ok got it