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Which of the following is the formula for this geometric sequence? 1, -3, 9, -27,...
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an = -1(3)n-1 an = 1(-3)n-1 an = 3(-1)n-1
Think: What is a geometric sequence. It's a sequence of the form ar^n. divide any term by the previous term to find r, then use the first term as a.
That will get you the answer.
Geometric sequence : \[\large a_n = a_1r^{n-1}\]\[\large r = -3 ... \frac{-3}{1}=-3 \ , \ \frac{9}{-3} = -3 \ , \ \frac{-27}{9} = -3\]\[\large a_1 = 1\]\[\large a_n = (1)(-3)^{n-1}\]
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