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Mathematics 9 Online
OpenStudy (anonymous):

factor: see below>>>>

OpenStudy (anonymous):

\[10b ^{3}+5b ^{2}-6b-3\]

OpenStudy (anonymous):

did anyone get \[(5b ^{2}-3)(2b+1)\]

OpenStudy (akashdeepdeb):

The answer is correct! yes!

OpenStudy (anonymous):

\[16x ^{3}-8x ^{2}y+2y-4x\]

OpenStudy (akashdeepdeb):

Gorup the first two terms together and the last 2 terms! 8x2(2x - y) - 2(2x - y) Now you have got 2 common factors! FACTORIZE :)

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