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factor: see below>>>>
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\[10b ^{3}+5b ^{2}-6b-3\]
did anyone get \[(5b ^{2}-3)(2b+1)\]
The answer is correct! yes!
\[16x ^{3}-8x ^{2}y+2y-4x\]
Gorup the first two terms together and the last 2 terms! 8x2(2x - y) - 2(2x - y) Now you have got 2 common factors! FACTORIZE :)
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