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An acute angle θ is in a right triangle with sin θ = seven eighths. What is the value of cot θ?
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We know cot theta = cos theta/sin theta So we gave to find cos theta to get our answer. In a right triangle there is a Perpendicular, base and a hypotenuse. And we know sin theta = Perp./Hyp. = 7/8 (Which is given as a ratio) So let perpendicular be 7x And hypotenuse. = 8x Find the base by Pythagorus' theorem and then find cos theta = Base/hypo. Then find cot theta by the relation given above. :)
So is it seven divided by the square root of fifteen
Yes! :) Kudos! :D
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