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Mathematics 27 Online
OpenStudy (anonymous):

evaluate integral of (x^2-y^2)/[(x^2+y^2)^2]dydx

OpenStudy (anonymous):

0 to 1

OpenStudy (anonymous):

both 0 to 1

OpenStudy (anonymous):

do you mean\[\int_0^1 \int_0^1 \frac{x^2-y^2}{(x^2+y^2)^2} \text{d}y \ \text{d}x\]

OpenStudy (anonymous):

aha ok

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

look at the figure

OpenStudy (anonymous):

|dw:1376503651430:dw|

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