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OpenStudy (anonymous):
Find g(1) if g(x) = x^2 + 1. 2 3 4
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OpenStudy (anonymous):
Insert 1 into your equation/function\[g(x) = x^2 + 1\]\[g(1) = 1^2 + 1\]What do you think is the answer?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
YUP!
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