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Suppose that the probability of a DVD player that was manufactured in a certain factory being defective is 2%. What is the probability that 3 DVD players are defective in a shipment of 13 DVD players from this factory? a. 0.0019 b. 286 c. 0.0023 d. 0.00176
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13C3 .02^3 .98^10=.00187
Same strategy as others
i dont see tht as a aswer choice tho @ybarrap
round to the nearest 10-thou place, you get .0019
I really need to tutor you \(\ddot\smile\)
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