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Mathematics
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solve the triangle A= 45, a= 31, b=27
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|dw:1376530543020:dw|
use cos theorem to find AB
31^2=(AB)^2+27^2-2(AB)*27*cos45
AB=x x^2-2*27*cos45*x+27^2-31^2=0
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BTW what do you mean solve the triangle ?
since x is length, x cannot be negative take positive one..
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