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Mathematics 16 Online
OpenStudy (anonymous):

Which of the following is not true for the equation y= x + 5? A) The output is 6 for an input of 1. B) When the independent variable is negative one, the dependent variable is 4. C)(3,2) is a solution D)When x is 7, y is 12

OpenStudy (anonymous):

Im stuck on B and C

OpenStudy (ankit042):

I think you are right :D

OpenStudy (skullpatrol):

Would you please explain your reasoning?

OpenStudy (anonymous):

what do you mean by reasoning

OpenStudy (skullpatrol):

Why do you think A is true?

OpenStudy (anonymous):

If you add 5 to 1 It's 6

OpenStudy (skullpatrol):

Yes, now how about B?

OpenStudy (anonymous):

I don't really understand B

OpenStudy (skullpatrol):

B) When the independent variable is negative one, the dependent variable is 4.

OpenStudy (anonymous):

I know but I don't understand it

OpenStudy (skullpatrol):

The independent variable is x and the dependent variable is y.

OpenStudy (anonymous):

So B is true

OpenStudy (skullpatrol):

Why?

OpenStudy (anonymous):

-1 + 5 is 4

OpenStudy (skullpatrol):

Yes, now how about C?

OpenStudy (skullpatrol):

C)(3,2) is a solution

OpenStudy (anonymous):

Ok so it C is the correct Answer because 7 + 5 =12

OpenStudy (skullpatrol):

The question asks: Which of the following is not true for the equation y= x + 5?

OpenStudy (anonymous):

the only one that is left is C)

OpenStudy (skullpatrol):

Yes, show me how it is not true that (3,2) is a solution.

OpenStudy (anonymous):

We already crossed out all the answer choices

OpenStudy (skullpatrol):

You said A, B and D are all true, so that only leaves C, but I want you to show me how C is false.

OpenStudy (anonymous):

3,2 are not solution

OpenStudy (skullpatrol):

Why?

OpenStudy (anonymous):

I don't know lol

OpenStudy (skullpatrol):

(3,2) means x=3 and y=2 because they give you the numbers in this (x,y) form, alphabetically.

OpenStudy (anonymous):

That's impossible C is the answer

OpenStudy (anonymous):

Yay Lol ( :

OpenStudy (skullpatrol):

$$2 \neq 8$$

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