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Which is the simplified form of 16 times a to the eighth power all over 12 times a to the fourth power.?
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please help :(
4a^4/3
4 over 3. a4 4a2 4a4 4 over 3. a2
would it be the first one then?
@jim_thompson5910 hmm hold on.
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i believe so but hold on.
okayy
\[\large \frac{16a^8}{12a^4}\] \[\large \frac{16}{12}*\frac{a^8}{a^4}\] \[\large \frac{4}{3}*\frac{a^8}{a^4}\] \[\large \frac{4}{3}*\frac{a^{8-4}}{1}\] \[\large \frac{4}{3}*\frac{a^4}{1}\] \[\large \frac{4}{3}a^4\] so it looks like you're correct
okay sweet! thanks guys
Jim is a big help.
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thx str99 and you're welcome
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