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It is being given that 1 is one of the zeroes of the polynomial 7x-x^3-6.Find its other zeroes
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|dw:1376602161725:dw| \[1*-6=-6,3-2=1,3*-2=-6\] \[x ^{2}+3x-2x-6=0\] make factors and find the values of x,these are other zeroes.
I didnt get :\
\[x \left( x+3 \right)-2\left( x+3 \right)=0\] \[\left( x+3 \right)\left( x-2 \right)=0\] now can you solve?
Okay ._. x+3=0 x=-3 Similarly, x-2=0 x=2 Is that right?
correct.
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