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Complete the square to solve the equation below? Check all that apply. x^2-10x-5=9
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A.\[5+\sqrt{39}\]
\[x^2-10x=14\]
B.\[-10-\sqrt{24}\]
C.\[5-\sqrt{39}\]
D.\[10+\sqrt{24}\]
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so can someone help
$$x^2-10x-14=0\\ (x-10/2)^2-14-(10/2)^2=0\\ =(x-5)^2-39=0\\ =(x-5)^2=39\\ (x-5)=\pm\sqrt{39}\\ x=5\pm\sqrt{39}$$
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